-5(t+2)-t-7=-6(t+5)+13

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Solution for -5(t+2)-t-7=-6(t+5)+13 equation: 



-5(t+2)-t-7=-6(t+5)+13

We move all terms to the left:

-5(t+2)-t-7-(-6(t+5)+13)=0

We add all the numbers together, and all the variables

-1t-5(t+2)-(-6(t+5)+13)-7=0

We multiply parentheses

-1t-5t-(-6(t+5)+13)-10-7=0



We calculate terms in parentheses: -(-6(t+5)+13), so:

-6(t+5)+13

We multiply parentheses

-6t-30+13

We add all the numbers together, and all the variables

-6t-17

Back to the equation:

-(-6t-17)



We add all the numbers together, and all the variables

-6t-(-6t-17)-17=0

We get rid of parentheses

-6t+6t+17-17=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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