-5(r-3)=2(r-10)

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Solution for -5(r-3)=2(r-10) equation: 



-5(r-3)=2(r-10)

We move all terms to the left:

-5(r-3)-(2(r-10))=0

We multiply parentheses

-5r-(2(r-10))+15=0



We calculate terms in parentheses: -(2(r-10)), so:

2(r-10)

We multiply parentheses

2r-20

Back to the equation:

-(2r-20)



We get rid of parentheses

-5r-2r+20+15=0

We add all the numbers together, and all the variables

-7r+35=0

We move all terms containing r to the left, all other terms to the right

-7r=-35

r=-35/-7

r=+5

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