-5(f+2)=2(3-f)

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Solution for -5(f+2)=2(3-f) equation:



-5(f+2)=2(3-f)
We move all terms to the left:
-5(f+2)-(2(3-f))=0
We add all the numbers together, and all the variables
-5(f+2)-(2(-1f+3))=0
We multiply parentheses
-5f-(2(-1f+3))-10=0
We calculate terms in parentheses: -(2(-1f+3)), so:
2(-1f+3)
We multiply parentheses
-2f+6
Back to the equation:
-(-2f+6)
We get rid of parentheses
-5f+2f-6-10=0
We add all the numbers together, and all the variables
-3f-16=0
We move all terms containing f to the left, all other terms to the right
-3f=16
f=16/-3
f=-5+1/3

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