-5(4y-5)-y=-4(y-2)

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Solution for -5(4y-5)-y=-4(y-2) equation: 



-5(4y-5)-y=-4(y-2)

We move all terms to the left:

-5(4y-5)-y-(-4(y-2))=0

We add all the numbers together, and all the variables

-1y-5(4y-5)-(-4(y-2))=0

We multiply parentheses

-1y-20y-(-4(y-2))+25=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

-21y-(-4y+8)+25=0

We get rid of parentheses

-21y+4y-8+25=0

We add all the numbers together, and all the variables

-17y+17=0

We move all terms containing y to the left, all other terms to the right

-17y=-17

y=-17/-17

y=1

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