-5(4y-3)+6y=3+2(2y-2)

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Solution for -5(4y-3)+6y=3+2(2y-2) equation: 



-5(4y-3)+6y=3+2(2y-2)

We move all terms to the left:

-5(4y-3)+6y-(3+2(2y-2))=0

We add all the numbers together, and all the variables

6y-5(4y-3)-(3+2(2y-2))=0

We multiply parentheses

6y-20y-(3+2(2y-2))+15=0



We calculate terms in parentheses: -(3+2(2y-2)), so:

3+2(2y-2)

determiningTheFunctionDomain
2(2y-2)+3

We multiply parentheses

4y-4+3

We add all the numbers together, and all the variables

4y-1

Back to the equation:

-(4y-1)



We add all the numbers together, and all the variables

-14y-(4y-1)+15=0

We get rid of parentheses

-14y-4y+1+15=0

We add all the numbers together, and all the variables

-18y+16=0

We move all terms containing y to the left, all other terms to the right

-18y=-16

y=-16/-18

y=8/9

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