-5(4y+3)-5=-8(y+6)+4y

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Solution for -5(4y+3)-5=-8(y+6)+4y equation: 



-5(4y+3)-5=-8(y+6)+4y

We move all terms to the left:

-5(4y+3)-5-(-8(y+6)+4y)=0

We multiply parentheses

-20y-(-8(y+6)+4y)-15-5=0



We calculate terms in parentheses: -(-8(y+6)+4y), so:

-8(y+6)+4y

We add all the numbers together, and all the variables

4y-8(y+6)

We multiply parentheses

4y-8y-48

We add all the numbers together, and all the variables

-4y-48

Back to the equation:

-(-4y-48)



We add all the numbers together, and all the variables

-20y-(-4y-48)-20=0

We get rid of parentheses

-20y+4y+48-20=0

We add all the numbers together, and all the variables

-16y+28=0

We move all terms containing y to the left, all other terms to the right

-16y=-28

y=-28/-16

y=1+3/4

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