-5(4t-4)=2(1-10t)+18

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Solution for -5(4t-4)=2(1-10t)+18 equation:


Simplifying
-5(4t + -4) = 2(1 + -10t) + 18

Reorder the terms:
-5(-4 + 4t) = 2(1 + -10t) + 18
(-4 * -5 + 4t * -5) = 2(1 + -10t) + 18
(20 + -20t) = 2(1 + -10t) + 18
20 + -20t = (1 * 2 + -10t * 2) + 18
20 + -20t = (2 + -20t) + 18

Reorder the terms:
20 + -20t = 2 + 18 + -20t

Combine like terms: 2 + 18 = 20
20 + -20t = 20 + -20t

Add '-20' to each side of the equation.
20 + -20 + -20t = 20 + -20 + -20t

Combine like terms: 20 + -20 = 0
0 + -20t = 20 + -20 + -20t
-20t = 20 + -20 + -20t

Combine like terms: 20 + -20 = 0
-20t = 0 + -20t
-20t = -20t

Add '20t' to each side of the equation.
-20t + 20t = -20t + 20t

Combine like terms: -20t + 20t = 0
0 = -20t + 20t

Combine like terms: -20t + 20t = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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