-5(4a-5)=2(3-10a)+19

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Solution for -5(4a-5)=2(3-10a)+19 equation: 


Simplifying
-5(4a + -5) = 2(3 + -10a) + 19

Reorder the terms:
-5(-5 + 4a) = 2(3 + -10a) + 19
(-5 * -5 + 4a * -5) = 2(3 + -10a) + 19
(25 + -20a) = 2(3 + -10a) + 19
25 + -20a = (3 * 2 + -10a * 2) + 19
25 + -20a = (6 + -20a) + 19

Reorder the terms:
25 + -20a = 6 + 19 + -20a

Combine like terms: 6 + 19 = 25
25 + -20a = 25 + -20a

Add '-25' to each side of the equation.
25 + -25 + -20a = 25 + -25 + -20a

Combine like terms: 25 + -25 = 0
0 + -20a = 25 + -25 + -20a
-20a = 25 + -25 + -20a

Combine like terms: 25 + -25 = 0
-20a = 0 + -20a
-20a = -20a

Add '20a' to each side of the equation.
-20a + 20a = -20a + 20a

Combine like terms: -20a + 20a = 0
0 = -20a + 20a

Combine like terms: -20a + 20a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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