-5(4-2x)=8-3(x+5)

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Solution for -5(4-2x)=8-3(x+5) equation: 



-5(4-2x)=8-3(x+5)

We move all terms to the left:

-5(4-2x)-(8-3(x+5))=0

We add all the numbers together, and all the variables

-5(-2x+4)-(8-3(x+5))=0

We multiply parentheses

10x-(8-3(x+5))-20=0



We calculate terms in parentheses: -(8-3(x+5)), so:

8-3(x+5)

determiningTheFunctionDomain
-3(x+5)+8

We multiply parentheses

-3x-15+8

We add all the numbers together, and all the variables

-3x-7

Back to the equation:

-(-3x-7)



We get rid of parentheses

10x+3x+7-20=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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