-5(3y-7)-y=-4(y-5)

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Solution for -5(3y-7)-y=-4(y-5) equation: 



-5(3y-7)-y=-4(y-5)

We move all terms to the left:

-5(3y-7)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-5(3y-7)-(-4(y-5))=0

We multiply parentheses

-1y-15y-(-4(y-5))+35=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We add all the numbers together, and all the variables

-16y-(-4y+20)+35=0

We get rid of parentheses

-16y+4y-20+35=0

We add all the numbers together, and all the variables

-12y+15=0

We move all terms containing y to the left, all other terms to the right

-12y=-15

y=-15/-12

y=1+1/4

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