-5(3x-9)=2(x-41)-43

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Solution for -5(3x-9)=2(x-41)-43 equation: 



-5(3x-9)=2(x-41)-43

We move all terms to the left:

-5(3x-9)-(2(x-41)-43)=0

We multiply parentheses

-15x-(2(x-41)-43)+45=0



We calculate terms in parentheses: -(2(x-41)-43), so:

2(x-41)-43

We multiply parentheses

2x-82-43

We add all the numbers together, and all the variables

2x-125

Back to the equation:

-(2x-125)



We get rid of parentheses

-15x-2x+125+45=0

We add all the numbers together, and all the variables

-17x+170=0

We move all terms containing x to the left, all other terms to the right

-17x=-170

x=-170/-17

x=+10

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