-5(3x-5)=2(x-7)-29

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Solution for -5(3x-5)=2(x-7)-29 equation: 



-5(3x-5)=2(x-7)-29

We move all terms to the left:

-5(3x-5)-(2(x-7)-29)=0

We multiply parentheses

-15x-(2(x-7)-29)+25=0



We calculate terms in parentheses: -(2(x-7)-29), so:

2(x-7)-29

We multiply parentheses

2x-14-29

We add all the numbers together, and all the variables

2x-43

Back to the equation:

-(2x-43)



We get rid of parentheses

-15x-2x+43+25=0

We add all the numbers together, and all the variables

-17x+68=0

We move all terms containing x to the left, all other terms to the right

-17x=-68

x=-68/-17

x=+4

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