-5(3x-3)=2(x-39)-43

Solution for -5(3x-3)=2(x-39)-43 equation:

-5(3x-3)=2(x-39)-43

We move all terms to the left:

-5(3x-3)-(2(x-39)-43)=0

We multiply parentheses

-15x-(2(x-39)-43)+15=0


We calculate terms in parentheses: -(2(x-39)-43), so:

2(x-39)-43

We multiply parentheses

2x-78-43

We add all the numbers together, and all the variables

2x-121

Back to the equation:

-(2x-121)


We get rid of parentheses

-15x-2x+121+15=0

We add all the numbers together, and all the variables

-17x+136=0

We move all terms containing x to the left, all other terms to the right

-17x=-136

x=-136/-17

x=+8