-5(3x-2)+8x-1=2(8-5x)

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Solution for -5(3x-2)+8x-1=2(8-5x) equation: 



-5(3x-2)+8x-1=2(8-5x)

We move all terms to the left:

-5(3x-2)+8x-1-(2(8-5x))=0

We add all the numbers together, and all the variables

-5(3x-2)+8x-(2(-5x+8))-1=0

We add all the numbers together, and all the variables

8x-5(3x-2)-(2(-5x+8))-1=0

We multiply parentheses

8x-15x-(2(-5x+8))+10-1=0



We calculate terms in parentheses: -(2(-5x+8)), so:

2(-5x+8)

We multiply parentheses

-10x+16

Back to the equation:

-(-10x+16)



We add all the numbers together, and all the variables

-7x-(-10x+16)+9=0

We get rid of parentheses

-7x+10x-16+9=0

We add all the numbers together, and all the variables

3x-7=0

We move all terms containing x to the left, all other terms to the right

3x=7

x=7/3

x=2+1/3

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