-5(3x+1)=-3(x-2)

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Solution for -5(3x+1)=-3(x-2) equation: 



-5(3x+1)=-3(x-2)

We move all terms to the left:

-5(3x+1)-(-3(x-2))=0

We multiply parentheses

-15x-(-3(x-2))-5=0



We calculate terms in parentheses: -(-3(x-2)), so:

-3(x-2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

-15x+3x-6-5=0

We add all the numbers together, and all the variables

-12x-11=0

We move all terms containing x to the left, all other terms to the right

-12x=11

x=11/-12

x=-11/12

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