-5(3-12j)=3(-15+18j)

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Solution for -5(3-12j)=3(-15+18j) equation: 



-5(3-12j)=3(-15+18j)

We move all terms to the left:

-5(3-12j)-(3(-15+18j))=0

We add all the numbers together, and all the variables

-5(-12j+3)-(3(18j-15))=0

We multiply parentheses

60j-(3(18j-15))-15=0



We calculate terms in parentheses: -(3(18j-15)), so:

3(18j-15)

We multiply parentheses

54j-45

Back to the equation:

-(54j-45)



We get rid of parentheses

60j-54j+45-15=0

We add all the numbers together, and all the variables

6j+30=0

We move all terms containing j to the left, all other terms to the right

6j=-30

j=-30/6

j=-5

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