-5(2y-5)+y=3(y+9)

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Solution for -5(2y-5)+y=3(y+9) equation: 



-5(2y-5)+y=3(y+9)

We move all terms to the left:

-5(2y-5)+y-(3(y+9))=0

We add all the numbers together, and all the variables

y-5(2y-5)-(3(y+9))=0

We multiply parentheses

y-10y-(3(y+9))+25=0



We calculate terms in parentheses: -(3(y+9)), so:

3(y+9)

We multiply parentheses

3y+27

Back to the equation:

-(3y+27)



We add all the numbers together, and all the variables

-9y-(3y+27)+25=0

We get rid of parentheses

-9y-3y-27+25=0

We add all the numbers together, and all the variables

-12y-2=0

We move all terms containing y to the left, all other terms to the right

-12y=2

y=2/-12

y=-1/6

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