-5(2y-4)-y=-4(y-3)

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Solution for -5(2y-4)-y=-4(y-3) equation: 



-5(2y-4)-y=-4(y-3)

We move all terms to the left:

-5(2y-4)-y-(-4(y-3))=0

We add all the numbers together, and all the variables

-1y-5(2y-4)-(-4(y-3))=0

We multiply parentheses

-1y-10y-(-4(y-3))+20=0



We calculate terms in parentheses: -(-4(y-3)), so:

-4(y-3)

We multiply parentheses

-4y+12

Back to the equation:

-(-4y+12)



We add all the numbers together, and all the variables

-11y-(-4y+12)+20=0

We get rid of parentheses

-11y+4y-12+20=0

We add all the numbers together, and all the variables

-7y+8=0

We move all terms containing y to the left, all other terms to the right

-7y=-8

y=-8/-7

y=1+1/7

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