-5(2y-3)-y=4(y-5)

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Solution for -5(2y-3)-y=4(y-5) equation:



-5(2y-3)-y=4(y-5)
We move all terms to the left:
-5(2y-3)-y-(4(y-5))=0
We add all the numbers together, and all the variables
-1y-5(2y-3)-(4(y-5))=0
We multiply parentheses
-1y-10y-(4(y-5))+15=0
We calculate terms in parentheses: -(4(y-5)), so:
4(y-5)
We multiply parentheses
4y-20
Back to the equation:
-(4y-20)
We add all the numbers together, and all the variables
-11y-(4y-20)+15=0
We get rid of parentheses
-11y-4y+20+15=0
We add all the numbers together, and all the variables
-15y+35=0
We move all terms containing y to the left, all other terms to the right
-15y=-35
y=-35/-15
y=2+1/3

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