-5(2y-3)+8y=5+2(5y-2)

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Solution for -5(2y-3)+8y=5+2(5y-2) equation: 



-5(2y-3)+8y=5+2(5y-2)

We move all terms to the left:

-5(2y-3)+8y-(5+2(5y-2))=0

We add all the numbers together, and all the variables

8y-5(2y-3)-(5+2(5y-2))=0

We multiply parentheses

8y-10y-(5+2(5y-2))+15=0



We calculate terms in parentheses: -(5+2(5y-2)), so:

5+2(5y-2)

determiningTheFunctionDomain
2(5y-2)+5

We multiply parentheses

10y-4+5

We add all the numbers together, and all the variables

10y+1

Back to the equation:

-(10y+1)



We add all the numbers together, and all the variables

-2y-(10y+1)+15=0

We get rid of parentheses

-2y-10y-1+15=0

We add all the numbers together, and all the variables

-12y+14=0

We move all terms containing y to the left, all other terms to the right

-12y=-14

y=-14/-12

y=1+1/6

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