-5(2y-2)-y=-4(y-4)

Solution for -5(2y-2)-y=-4(y-4) equation:

-5(2y-2)-y=-4(y-4)

We move all terms to the left:

-5(2y-2)-y-(-4(y-4))=0

We add all the numbers together, and all the variables

-1y-5(2y-2)-(-4(y-4))=0

We multiply parentheses

-1y-10y-(-4(y-4))+10=0


We calculate terms in parentheses: -(-4(y-4)), so:

-4(y-4)

We multiply parentheses

-4y+16

Back to the equation:

-(-4y+16)


We add all the numbers together, and all the variables

-11y-(-4y+16)+10=0

We get rid of parentheses

-11y+4y-16+10=0

We add all the numbers together, and all the variables

-7y-6=0

We move all terms containing y to the left, all other terms to the right

-7y=6

y=6/-7

y=-6/7