-5(2y-2)-y=-2(y-4)

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Solution for -5(2y-2)-y=-2(y-4) equation: 



-5(2y-2)-y=-2(y-4)

We move all terms to the left:

-5(2y-2)-y-(-2(y-4))=0

We add all the numbers together, and all the variables

-1y-5(2y-2)-(-2(y-4))=0

We multiply parentheses

-1y-10y-(-2(y-4))+10=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-11y-(-2y+8)+10=0

We get rid of parentheses

-11y+2y-8+10=0

We add all the numbers together, and all the variables

-9y+2=0

We move all terms containing y to the left, all other terms to the right

-9y=-2

y=-2/-9

y=2/9

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