-5(2x-1)=2(x-40)-35

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Solution for -5(2x-1)=2(x-40)-35 equation: 



-5(2x-1)=2(x-40)-35

We move all terms to the left:

-5(2x-1)-(2(x-40)-35)=0

We multiply parentheses

-10x-(2(x-40)-35)+5=0



We calculate terms in parentheses: -(2(x-40)-35), so:

2(x-40)-35

We multiply parentheses

2x-80-35

We add all the numbers together, and all the variables

2x-115

Back to the equation:

-(2x-115)



We get rid of parentheses

-10x-2x+115+5=0

We add all the numbers together, and all the variables

-12x+120=0

We move all terms containing x to the left, all other terms to the right

-12x=-120

x=-120/-12

x=+10

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