-5(2x+3)-(2x+20)-35=(5x-4)

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Solution for -5(2x+3)-(2x+20)-35=(5x-4) equation: 



-5(2x+3)-(2x+20)-35=(5x-4)

We move all terms to the left:

-5(2x+3)-(2x+20)-35-((5x-4))=0

We multiply parentheses

-10x-(2x+20)-((5x-4))-15-35=0

We get rid of parentheses

-10x-2x-((5x-4))-20-15-35=0



We calculate terms in parentheses: -((5x-4)), so:

(5x-4)

We get rid of parentheses

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

-12x-(5x-4)-70=0

We get rid of parentheses

-12x-5x+4-70=0

We add all the numbers together, and all the variables

-17x-66=0

We move all terms containing x to the left, all other terms to the right

-17x=66

x=66/-17

x=-3+15/17

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