-5(2w-2)8w=2(w+4)

Solution for -5(2w-2)8w=2(w+4) equation:

-5(2w-2)8w=2(w+4)

We move all terms to the left:

-5(2w-2)8w-(2(w+4))=0

We multiply parentheses

-80w^2+80w-(2(w+4))=0


We calculate terms in parentheses: -(2(w+4)), so:

2(w+4)

We multiply parentheses

2w+8

Back to the equation:

-(2w+8)


We get rid of parentheses

-80w^2+80w-2w-8=0

We add all the numbers together, and all the variables

-80w^2+78w-8=0

a = -80; b = 78; c = -8;
Δ = b2-4ac
Δ = 782-4·(-80)·(-8)
Δ = 3524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3524}=\sqrt{4*881}=\sqrt{4}*\sqrt{881}=2\sqrt{881}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-2\sqrt{881}}{2*-80}=\frac{-78-2\sqrt{881}}{-160}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+2\sqrt{881}}{2*-80}=\frac{-78+2\sqrt{881}}{-160}
$