-5(28f-28)-42=-14(12f-12)+70f

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Solution for -5(28f-28)-42=-14(12f-12)+70f equation: 



-5(28f-28)-42=-14(12f-12)+70f

We move all terms to the left:

-5(28f-28)-42-(-14(12f-12)+70f)=0

We multiply parentheses

-140f-(-14(12f-12)+70f)+140-42=0



We calculate terms in parentheses: -(-14(12f-12)+70f), so:

-14(12f-12)+70f

We add all the numbers together, and all the variables

70f-14(12f-12)

We multiply parentheses

70f-168f+168

We add all the numbers together, and all the variables

-98f+168

Back to the equation:

-(-98f+168)



We add all the numbers together, and all the variables

-140f-(-98f+168)+98=0

We get rid of parentheses

-140f+98f-168+98=0

We add all the numbers together, and all the variables

-42f-70=0

We move all terms containing f to the left, all other terms to the right

-42f=70

f=70/-42

f=-1+2/3

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