-5(2+4r)+5r=6(3-3r)-4

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Solution for -5(2+4r)+5r=6(3-3r)-4 equation: 



-5(2+4r)+5r=6(3-3r)-4

We move all terms to the left:

-5(2+4r)+5r-(6(3-3r)-4)=0

We add all the numbers together, and all the variables

-5(4r+2)+5r-(6(-3r+3)-4)=0

We add all the numbers together, and all the variables

5r-5(4r+2)-(6(-3r+3)-4)=0

We multiply parentheses

5r-20r-(6(-3r+3)-4)-10=0



We calculate terms in parentheses: -(6(-3r+3)-4), so:

6(-3r+3)-4

We multiply parentheses

-18r+18-4

We add all the numbers together, and all the variables

-18r+14

Back to the equation:

-(-18r+14)



We add all the numbers together, and all the variables

-15r-(-18r+14)-10=0

We get rid of parentheses

-15r+18r-14-10=0

We add all the numbers together, and all the variables

3r-24=0

We move all terms containing r to the left, all other terms to the right

3r=24

r=24/3

r=8

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