-5(-x-4)+20=19-3(1x-2)

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Solution for -5(-x-4)+20=19-3(1x-2) equation: 



-5(-x-4)+20=19-3(1x-2)

We move all terms to the left:

-5(-x-4)+20-(19-3(1x-2))=0

We add all the numbers together, and all the variables

-5(-1x-4)-(19-3(x-2))+20=0

We multiply parentheses

5x-(19-3(x-2))+20+20=0



We calculate terms in parentheses: -(19-3(x-2)), so:

19-3(x-2)

determiningTheFunctionDomain
-3(x-2)+19

We multiply parentheses

-3x+6+19

We add all the numbers together, and all the variables

-3x+25

Back to the equation:

-(-3x+25)



We add all the numbers together, and all the variables

5x-(-3x+25)+40=0

We get rid of parentheses

5x+3x-25+40=0

We add all the numbers together, and all the variables

8x+15=0

We move all terms containing x to the left, all other terms to the right

8x=-15

x=-15/8

x=-1+7/8

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