-5(-4y+2)-5y=7(y-2)-2

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Solution for -5(-4y+2)-5y=7(y-2)-2 equation: 



-5(-4y+2)-5y=7(y-2)-2

We move all terms to the left:

-5(-4y+2)-5y-(7(y-2)-2)=0

We add all the numbers together, and all the variables

-5y-5(-4y+2)-(7(y-2)-2)=0

We multiply parentheses

-5y+20y-(7(y-2)-2)-10=0



We calculate terms in parentheses: -(7(y-2)-2), so:

7(y-2)-2

We multiply parentheses

7y-14-2

We add all the numbers together, and all the variables

7y-16

Back to the equation:

-(7y-16)



We add all the numbers together, and all the variables

15y-(7y-16)-10=0

We get rid of parentheses

15y-7y+16-10=0

We add all the numbers together, and all the variables

8y+6=0

We move all terms containing y to the left, all other terms to the right

8y=-6

y=-6/8

y=-3/4

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