-5(-3y+5)-8y=3(y-6)-1

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Solution for -5(-3y+5)-8y=3(y-6)-1 equation: 



-5(-3y+5)-8y=3(y-6)-1

We move all terms to the left:

-5(-3y+5)-8y-(3(y-6)-1)=0

We add all the numbers together, and all the variables

-8y-5(-3y+5)-(3(y-6)-1)=0

We multiply parentheses

-8y+15y-(3(y-6)-1)-25=0



We calculate terms in parentheses: -(3(y-6)-1), so:

3(y-6)-1

We multiply parentheses

3y-18-1

We add all the numbers together, and all the variables

3y-19

Back to the equation:

-(3y-19)



We add all the numbers together, and all the variables

7y-(3y-19)-25=0

We get rid of parentheses

7y-3y+19-25=0

We add all the numbers together, and all the variables

4y-6=0

We move all terms containing y to the left, all other terms to the right

4y=6

y=6/4

y=1+1/2

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