-5(-3y+4)-3=2(y-4)-4

Solution for -5(-3y+4)-3=2(y-4)-4 equation:

-5(-3y+4)-3=2(y-4)-4

We move all terms to the left:

-5(-3y+4)-3-(2(y-4)-4)=0

We multiply parentheses

15y-(2(y-4)-4)-20-3=0


We calculate terms in parentheses: -(2(y-4)-4), so:

2(y-4)-4

We multiply parentheses

2y-8-4

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)


We add all the numbers together, and all the variables

15y-(2y-12)-23=0

We get rid of parentheses

15y-2y+12-23=0

We add all the numbers together, and all the variables

13y-11=0

We move all terms containing y to the left, all other terms to the right

13y=11

y=11/13

y=11/13