-4y+3(y-8)=7(2y-4)-11

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Solution for -4y+3(y-8)=7(2y-4)-11 equation: 



-4y+3(y-8)=7(2y-4)-11

We move all terms to the left:

-4y+3(y-8)-(7(2y-4)-11)=0

We multiply parentheses

-4y+3y-(7(2y-4)-11)-24=0



We calculate terms in parentheses: -(7(2y-4)-11), so:

7(2y-4)-11

We multiply parentheses

14y-28-11

We add all the numbers together, and all the variables

14y-39

Back to the equation:

-(14y-39)



We add all the numbers together, and all the variables

-1y-(14y-39)-24=0

We get rid of parentheses

-1y-14y+39-24=0

We add all the numbers together, and all the variables

-15y+15=0

We move all terms containing y to the left, all other terms to the right

-15y=-15

y=-15/-15

y=1

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