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-4x^2=-8-10x
We move all terms to the left:
-4x^2-(-8-10x)=0
We add all the numbers together, and all the variables
-4x^2-(-10x-8)=0
We get rid of parentheses
-4x^2+10x+8=0
a = -4; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·(-4)·8
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{57}}{2*-4}=\frac{-10-2\sqrt{57}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{57}}{2*-4}=\frac{-10+2\sqrt{57}}{-8} $
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