-4x2+8x-4=0

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Solution for -4x2+8x-4=0 equation: 



-4x^2+8x-4=0

a = -4; b = 8; c = -4;
Δ = b2-4ac
Δ = 82-4·(-4)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-8}=1$

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