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-4x^2+15=8x^2+24x
We move all terms to the left:
-4x^2+15-(8x^2+24x)=0
We get rid of parentheses
-4x^2-8x^2-24x+15=0
We add all the numbers together, and all the variables
-12x^2-24x+15=0
a = -12; b = -24; c = +15;
Δ = b2-4ac
Δ = -242-4·(-12)·15
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*-12}=\frac{-12}{-24} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*-12}=\frac{60}{-24} =-2+1/2 $
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