-4x-4=-4x(x+2)

Solution for -4x-4=-4x(x+2) equation:

-4x-4=-4x(x+2)

We move all terms to the left:

-4x-4-(-4x(x+2))=0


We calculate terms in parentheses: -(-4x(x+2)), so:

-4x(x+2)

We multiply parentheses

-4x^2-8x

Back to the equation:

-(-4x^2-8x)


We get rid of parentheses

4x^2+8x-4x-4=0

We add all the numbers together, and all the variables

4x^2+4x-4=0

a = 4; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·4·(-4)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{5}}{2*4}=\frac{-4-4\sqrt{5}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{5}}{2*4}=\frac{-4+4\sqrt{5}}{8}
$