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-4x+15=-7/2x+12
We move all terms to the left:
-4x+15-(-7/2x+12)=0
Domain of the equation: 2x+12)!=0We get rid of parentheses
x∈R
-4x+7/2x-12+15=0
We multiply all the terms by the denominator
-4x*2x-12*2x+15*2x+7=0
Wy multiply elements
-8x^2-24x+30x+7=0
We add all the numbers together, and all the variables
-8x^2+6x+7=0
a = -8; b = 6; c = +7;
Δ = b2-4ac
Δ = 62-4·(-8)·7
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{65}}{2*-8}=\frac{-6-2\sqrt{65}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{65}}{2*-8}=\frac{-6+2\sqrt{65}}{-16} $
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