-4x+15-x=2(6-x)-x

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Solution for -4x+15-x=2(6-x)-x equation: 



-4x+15-x=2(6-x)-x

We move all terms to the left:

-4x+15-x-(2(6-x)-x)=0

We add all the numbers together, and all the variables

-4x-x-(2(-1x+6)-x)+15=0

We add all the numbers together, and all the variables

-5x-(2(-1x+6)-x)+15=0



We calculate terms in parentheses: -(2(-1x+6)-x), so:

2(-1x+6)-x

We add all the numbers together, and all the variables

-1x+2(-1x+6)

We multiply parentheses

-1x-2x+12

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

-5x+3x-12+15=0

We add all the numbers together, and all the variables

-2x+3=0

We move all terms containing x to the left, all other terms to the right

-2x=-3

x=-3/-2

x=1+1/2

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