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-4x(x+3)=-28
We move all terms to the left:
-4x(x+3)-(-28)=0
We add all the numbers together, and all the variables
-4x(x+3)+28=0
We multiply parentheses
-4x^2-12x+28=0
a = -4; b = -12; c = +28;
Δ = b2-4ac
Δ = -122-4·(-4)·28
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{37}}{2*-4}=\frac{12-4\sqrt{37}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{37}}{2*-4}=\frac{12+4\sqrt{37}}{-8} $
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