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-4x(x+13)+3x=80
We move all terms to the left:
-4x(x+13)+3x-(80)=0
We add all the numbers together, and all the variables
3x-4x(x+13)-80=0
We multiply parentheses
-4x^2+3x-52x-80=0
We add all the numbers together, and all the variables
-4x^2-49x-80=0
a = -4; b = -49; c = -80;
Δ = b2-4ac
Δ = -492-4·(-4)·(-80)
Δ = 1121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{1121}}{2*-4}=\frac{49-\sqrt{1121}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{1121}}{2*-4}=\frac{49+\sqrt{1121}}{-8} $
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