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-4x(6x-2)=-40-8x
We move all terms to the left:
-4x(6x-2)-(-40-8x)=0
We add all the numbers together, and all the variables
-4x(6x-2)-(-8x-40)=0
We multiply parentheses
-24x^2+8x-(-8x-40)=0
We get rid of parentheses
-24x^2+8x+8x+40=0
We add all the numbers together, and all the variables
-24x^2+16x+40=0
a = -24; b = 16; c = +40;
Δ = b2-4ac
Δ = 162-4·(-24)·40
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-64}{2*-24}=\frac{-80}{-48} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+64}{2*-24}=\frac{48}{-48} =-1 $
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