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-4x(2x-5)+3x=11-2x
We move all terms to the left:
-4x(2x-5)+3x-(11-2x)=0
We add all the numbers together, and all the variables
-4x(2x-5)+3x-(-2x+11)=0
We add all the numbers together, and all the variables
3x-4x(2x-5)-(-2x+11)=0
We multiply parentheses
-8x^2+3x+20x-(-2x+11)=0
We get rid of parentheses
-8x^2+3x+20x+2x-11=0
We add all the numbers together, and all the variables
-8x^2+25x-11=0
a = -8; b = 25; c = -11;
Δ = b2-4ac
Δ = 252-4·(-8)·(-11)
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{273}}{2*-8}=\frac{-25-\sqrt{273}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{273}}{2*-8}=\frac{-25+\sqrt{273}}{-16} $
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