-4x(2x-1)=-3(3x+2)

Solution for -4x(2x-1)=-3(3x+2) equation:

-4x(2x-1)=-3(3x+2)

We move all terms to the left:

-4x(2x-1)-(-3(3x+2))=0

We multiply parentheses

-8x^2+4x-(-3(3x+2))=0


We calculate terms in parentheses: -(-3(3x+2)), so:

-3(3x+2)

We multiply parentheses

-9x-6

Back to the equation:

-(-9x-6)


We get rid of parentheses

-8x^2+4x+9x+6=0

We add all the numbers together, and all the variables

-8x^2+13x+6=0

a = -8; b = 13; c = +6;
Δ = b2-4ac
Δ = 132-4·(-8)·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-19}{2*-8}=\frac{-32}{-16}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+19}{2*-8}=\frac{6}{-16}
=-3/8
$