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-4x(2x+5)+x+2=-11
We move all terms to the left:
-4x(2x+5)+x+2-(-11)=0
We add all the numbers together, and all the variables
x-4x(2x+5)+13=0
We multiply parentheses
-8x^2+x-20x+13=0
We add all the numbers together, and all the variables
-8x^2-19x+13=0
a = -8; b = -19; c = +13;
Δ = b2-4ac
Δ = -192-4·(-8)·13
Δ = 777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{777}}{2*-8}=\frac{19-\sqrt{777}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{777}}{2*-8}=\frac{19+\sqrt{777}}{-16} $
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