-4x(-10-8x)=-(12x-14)4

Solution for -4x(-10-8x)=-(12x-14)4 equation:

-4x(-10-8x)=-(12x-14)4

We move all terms to the left:

-4x(-10-8x)-(-(12x-14)4)=0

We add all the numbers together, and all the variables

-4x(-8x-10)-(-(12x-14)4)=0

We multiply parentheses

32x^2+40x-(-(12x-14)4)=0


We calculate terms in parentheses: -(-(12x-14)4), so:

-(12x-14)4

We multiply parentheses

-48x+56

Back to the equation:

-(-48x+56)


We get rid of parentheses

32x^2+40x+48x-56=0

We add all the numbers together, and all the variables

32x^2+88x-56=0

a = 32; b = 88; c = -56;
Δ = b2-4ac
Δ = 882-4·32·(-56)
Δ = 14912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14912}=\sqrt{64*233}=\sqrt{64}*\sqrt{233}=8\sqrt{233}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-8\sqrt{233}}{2*32}=\frac{-88-8\sqrt{233}}{64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+8\sqrt{233}}{2*32}=\frac{-88+8\sqrt{233}}{64}
$