-4x(-10-8x)=-(12x-14)

Solution for -4x(-10-8x)=-(12x-14) equation:

-4x(-10-8x)=-(12x-14)

We move all terms to the left:

-4x(-10-8x)-(-(12x-14))=0

We add all the numbers together, and all the variables

-4x(-8x-10)-(-(12x-14))=0

We multiply parentheses

32x^2+40x-(-(12x-14))=0


We calculate terms in parentheses: -(-(12x-14)), so:

-(12x-14)

We get rid of parentheses

-12x+14

Back to the equation:

-(-12x+14)


We get rid of parentheses

32x^2+40x+12x-14=0

We add all the numbers together, and all the variables

32x^2+52x-14=0

a = 32; b = 52; c = -14;
Δ = b2-4ac
Δ = 522-4·32·(-14)
Δ = 4496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4496}=\sqrt{16*281}=\sqrt{16}*\sqrt{281}=4\sqrt{281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-4\sqrt{281}}{2*32}=\frac{-52-4\sqrt{281}}{64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+4\sqrt{281}}{2*32}=\frac{-52+4\sqrt{281}}{64}
$