-4m+8-2(m+3)=2(2m-4)

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Solution for -4m+8-2(m+3)=2(2m-4) equation: 



-4m+8-2(m+3)=2(2m-4)

We move all terms to the left:

-4m+8-2(m+3)-(2(2m-4))=0

We multiply parentheses

-4m-2m-(2(2m-4))-6+8=0



We calculate terms in parentheses: -(2(2m-4)), so:

2(2m-4)

We multiply parentheses

4m-8

Back to the equation:

-(4m-8)



We add all the numbers together, and all the variables

-6m-(4m-8)+2=0

We get rid of parentheses

-6m-4m+8+2=0

We add all the numbers together, and all the variables

-10m+10=0

We move all terms containing m to the left, all other terms to the right

-10m=-10

m=-10/-10

m=1

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