-4m+12=2(6-2m)

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Solution for -4m+12=2(6-2m) equation: 



-4m+12=2(6-2m)

We move all terms to the left:

-4m+12-(2(6-2m))=0

We add all the numbers together, and all the variables

-4m-(2(-2m+6))+12=0



We calculate terms in parentheses: -(2(-2m+6)), so:

2(-2m+6)

We multiply parentheses

-4m+12

Back to the equation:

-(-4m+12)



We get rid of parentheses

-4m+4m-12+12=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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