-4k+10=3(2-k)

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Solution for -4k+10=3(2-k) equation:



-4k+10=3(2-k)
We move all terms to the left:
-4k+10-(3(2-k))=0
We add all the numbers together, and all the variables
-4k-(3(-1k+2))+10=0
We calculate terms in parentheses: -(3(-1k+2)), so:
3(-1k+2)
We multiply parentheses
-3k+6
Back to the equation:
-(-3k+6)
We get rid of parentheses
-4k+3k-6+10=0
We add all the numbers together, and all the variables
-1k+4=0
We move all terms containing k to the left, all other terms to the right
-k=-4
k=-4/-1
k=+4

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