-4cos(2x-pi/6)=0

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Solution for -4cos(2x-pi/6)=0 equation: 


x in (-oo:+oo)

-4*cos(2*x-(pi/6)) = 0

cos(2*x-(pi/6)) = 0

cos(2*x-(pi/6)) = 0  <=>  2*x-(pi/6) = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

2*x-t_1-(pi/6) = 0

2*x-t_1-(pi/6) = 0 // + -t_1-(pi/6)

2*x = -(-t_1-(pi/6)) // : 2

x = (-(-t_1-(pi/6)))/2

x = (t_1+pi/6)/2

x = (pi*k_1+pi/2+pi/6)/2 i k_1 należy do I

-4*cos(2*x-(pi/6)) = 0  <=>  -4 = 0 or -4*cos(2*x-(pi/6)) = 0  <=>  cos(2*x-(pi/6)) = 0

x = (pi*k_1+pi/2+pi/6)/2

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